Class 11 Chemistry Mole Concept MCQs JEE/NEET
Mole Concept JEE/NEET
Multiple Choice Questions with One Correct Answer
1. Which of the following is not a mixture?
(a) Gasoline (b) Distilled alcohol
(c) LPG (d) Iodized table salt
2. If 6.3 g of NaHCO3 is added to 15.0 g CH3COOH solution, the residue is found to weigh 18.0 g. What is the mass of CO2 released in the reaction?
(a) 4.5 g (b) 3.3 g
(c) 2.6 g (d) 2.8 g
3. 0.003924 have . . . . . significant figures.
(a) 6 (b) 4
(c) 3 (d) 7
4. The solid-like conducting state of gases with free electrons is called
(a) sol state (b) gel state
(c) plasma state (d) All of these
5. The mass of nitrogen per gram hydrogen in the compound hydrazine is exactly one and a half times the mass of nitrogen in the compound ammonia. This fact illustrates the
(a) law of conservation of mass
(b) multiple valencies of nitrogen
(c) law of multiple proportions
(d) law of definite proportions
6. The answer to the calculation

significant figures will be
(a) 3.579 (b) 3.570
(c) 3.57 (d) 3.6
7. Carbon dioxide contains 27.27% of carbon, carbon disulphide contains 15.79% of carbon and sulphur dioxide contains 50% of sulphur. This data is an agreement with
(a) law of conservation of mass
(b) law of definite proportions
(c) law of multiple proportions
(d) law of reciprocal proportions
8. Unit J Pa–1 is equivalent to
(a) m3 (b) cm3
(d) dm3 (d) None of these
9. In multiplication and division, the significant figures of the answer must be the same as that in the quantity with ………….. a number of significant figures.
(a) maximum (b) 3
(c) 2 (d) minimum
10. One part of element A combines with two parts of another element B. 6 parts of element C combines with 4 parts of B. If A and C combine together, the ratio of their weights will be governed by
(a) law of definite proportions
(b) law of multiple proportions
(c) law of reciprocal proportions
(d) law of conservation of mass
11. The matter is anything which occupies . . . A . . . and has . . . B . . . Here A and B are.
(a) density and mass (b) volume and mass
(c) space and mass (d) None of these
12. How many significant figures are there in (respectively)(1) 73.000 g (2) 0.0503 g and (3) 2.001 s?
(a) 3, 3, 4 (b) 3, 4, 5
(c) 2, 5, 4 (d) 5, 3, 4
13. An example of a homogeneous mixture is
(a) a mixture of soil and water
(b) a mixture of salt and sand grains
(c) sugar solution
(d) None of the above
14. The number of significant figures in Avogadro’snumber is
(a) four (b) two
(c) three (d) can be any of these
15. n-gram of a substance X-reacts with m gram of substance Y to from p gram of substance R and q gram of substance S. This reaction can be represented as follows
X + Y = R + S
The relation which can be established in the amounts of the reactants and the products will be
(a) n – m = p – q (b) n + m = p + q
(c) n = m (d) p = q
16. One atom of an element X-weight 6.643 × 10–23 g. Number of moles of atoms in 20 kg is
(a) 140 (b) 150
(c) 250 (d) 500
17. A sample of ammonium phosphate (NH4)3PO4 contains 6.36 moles of hydrogen atoms. The number of moles of oxygen atoms in the sample is (atomic mass of N = 14.04, H = 1, P = 31, O = 16)
(a) 0.265 (b) 0.795 (c) 2.12 (d) 4.14
18. The sample with the largest number of atoms is
(a) 1 g of O2(g) (b) 1 g of Ni(s)
(c) 1 g of B(s) (d) 1 g of N2(g)
19. If H2SO4 ionises as H2SO4 + 2H2O → 2H3O+ + SO2–4, then total number of ions produced by 0.1 MH2SO4 will be
(a) 9.03 × 1021 (b) 3.01 × 1022
(c) 6.02 × 1022 (d) 1.8 ×1023
20. The number of sodium atoms in 2 moles of sodium ferrocyanide is
(a) 12 × 1023 (b) 26 × 1023
(c) 34 × 1023 (d) 48 × 1023
21. The molecular weight of air will be (N2—78%, O2—21%, Ar—0.9% and CO2—0.1%)
(a) 18.64 (b) 24.968
(c) 28.964 (d) 29.864
22. Out of 1.0 g dioxygen, 1.0g (atomic) oxygen and 1.0 g ozone, the maximum number of molecules are contained in
(a) 1.0 g of atomic oxygen
(b) 1.0 g of ozone
(c) 1.0 g of oxygen gas
(d) All contain same number of atoms
23. A sample of AlF3 contains 3.0 × 1024 F ions. The number of formula units in this sample is
(a) 9.0 × 1024 (b) 3.0 × 1024
(c) 0.75 × 1024 (d) 1.0 × 1024
24. How many of Al2(SO4)3 would be in 50 g of the substance? [UP SEE 2005]
(a) 0.083 mol (b) 0.952 mol
(c) 0.481 mol (d) 0.140 mol
25. If 0.5 moles of BaCl2 is mixed with 0.2 mole of Na3PO4, the maximum number of moles of Ba3(PO4)2 that can be formed is
(a) 0.7 (b) 0.5
(c) 0.03 (d) 0.10
26. Two elements X (at. wt. 75) and Y (at. wt. 16) combine to give a compound having 75.8% of X. The formula of compound will be
(a) XY (b) X2Y
(c) XY3 (d) X2Y3
27. A sample of copper sulphate pentahydrate contains 8.64 g of oxygen. How many grams of Cu is present in this sample?(Atomic mass of Cu = 63.6, S = 32.06, O = 16)
(a) 0.952 g (b) 3.816 g
(c) 3.782 g (d) 8.64 g
28. The number of water molecules present in a drop of water (volume 0.0018 mL) at room temperature is
(a) 6.023 × 1019 (b) 1.084 × 1018
(c) 4.84 × 1017 (d) 6.023 × 1023
29. Zinc sulphate contains 22.64% of zinc and 43.9% of water of crystallization. If the law of constant proportions is true then the weight of zinc required to produce 20 g of the crystals will be
(a) 45.3 g (g) 4.53 g
(c) 0.453 g (d) 453 g
30. Which of the following pairs contains equal number of atoms?
(a) 11.2 cc (STP) of nitrogen and 0.015 g of nitric oxide
(b) 22.4L (STP) of nitrous oxide and 22.4 L of nitric oxide
(c) 1 millimole of HCl and 0.5 millimoles of H2S
(d) 1 mole of H2O2 and 1 mole of N2O4
Answers
1. (b) 2. (b) 3. (b) 4. (c) 5. (c) 6. (d) 7. (d) 8. (a) 9. (d) 10. (c)
11. (c) 12. (d) 13. (c) 14. (a) 15. (b) 16. (d) 17. (c) 18. (c) 19. (d) 20. (d)
21. (c) 22. (a) 23. (d) 24. (d) 25. (d) 26. (d) 27. (b) 28. (a) 29. (b) 30. (a)
EXPLANATIONS

- According to the law of conservation of mass,
mass of reactants = mass of products
∴ 6.3 + 15.0 = 18.0 + x
or x = 21.3 – 18.0 = 3.3 g - As the ratio of masses of nitrogen per gram of hydrogen in hydrazine and NH3

i.e, the law of multiple proportions.

Answer in significant figures = 3.6
- In CS2
C: S mass ratio is 15.79: 84.21 15.79 parts of carbon combine with sulphur = 84.21
∴ 27.27 parts of carbon will combine with


Hence, the ratio of S: O is 145.434: 72.73 i.e, 2: 1
In SO2, the ratio of S: O is 1: 1
Since, the ratio of S: O is a simple whole-number ratio, therefore the law of reciprocal proportions is proved.

The atomic weight of the element
X = 6.643 × 10–23 × NA = 40

17. 1 mole of (NH4)3PO4 contains 12 moles of hydrogen atoms.
∴ 12 moles of hydrogen atoms = 1 mole of (NH4)3PO4.
∴ 1 mole of hydrogen atom =1/12 mole of (NH4)3PO4


Alternative: The smaller the atomic mass, larger will be the no. of atoms in the sample.
19. 1 mol of H2SO4 gives = 3 moles of ions or 3 ×6.023 ×1023 ions
∴ 0.1 mole of H2SO4 will give = 0.1 × 3 × 6.023 × 1023 ions
= 1.8 × 1023 ions

24.

Given that the mass of Al2(SO4)3 = 50 g
The molecular mass of Al2(SO4)3 = 342


Here, Na3PO4 is the limiting reactant.
2 moles of Na3PO4 gives 1 mole of Ba3(PO4)2
So, 0.2 moles of Na3PO4 will give 0.1 moles of Ba3(PO4)2.


